Calculus 10th Edition

Published by Brooks Cole
ISBN 10: 1-28505-709-0
ISBN 13: 978-1-28505-709-5

Chapter 3 - Applications of Differentiation - 3.9 Exercises - Page 236: 5

Answer

\[\boxed{\begin{array}{*{20}{c}} x&{1.9}&{1.99}&2&{2.01}&{2.1} \\ {f\left( x \right)}&{0.9463}&{0.9134}&{0.9093}&{0.9051}&{0.8632} \\ {T\left( x \right)}&{0.9509}&{0.9135}&{0.9093}&{0.9051}&{0.8677} \end{array}}\]

Work Step by Step

$$\eqalign{ & f\left( x \right) = \sin x,{\text{ }}\left( {2,\sin 2} \right) \cr & {\text{Differentiate}} \cr & f'\left( x \right) = \cos x \cr & f'\left( 2 \right) = \cos \left( 2 \right) \cr & {\text{The equation for the tangent line at the point }}\left( {c,f\left( c \right)} \right){\text{ is:}} \cr & y = f\left( c \right) + f'\left( c \right)\left( {x - c} \right) \cr & {\text{We have the point }}\left( {2,\sqrt 2 } \right) \cr & \to c = 2,{\text{ }}f\left( c \right) = \sin 2,{\text{ }}f'\left( c \right) = \cos \left( 2 \right) \cr & y = \sin \left( 2 \right) + \cos \left( 2 \right)\left( {x - 2} \right) \cr & T\left( x \right) = \cos \left( 2 \right)\left( {x - 2} \right) + \sin \left( 2 \right) \cr & {\text{Completing the table for }}f\left( x \right){\text{:}} \cr & x = 1.9 \to f\left( {1.9} \right) = \sin \left( {1.9} \right) = 0.9463 \cr & x = 1.99 \to f\left( {1.99} \right) = \sin \left( {1.99} \right) = 0.9134 \cr & x = 2 \to f\left( 2 \right) = \sin \left( 2 \right) = 0.9093 \cr & x = 2.01 \to f\left( {2.01} \right) = \sin \left( {2.01} \right) = 0.9051 \cr & x = 2.1 \to f\left( {2.1} \right) = \sin \left( {2.1} \right) = 0.8632 \cr & {\text{Completing the table for }}T\left( x \right){\text{:}} \cr & x = 1.9 \to T\left( {1.9} \right) = \cos \left( 2 \right)\left( {1.9 - 2} \right) + \sin \left( 2 \right) = 0.9509 \cr & x = 1.99 \to T\left( {1.99} \right) = \cos \left( 2 \right)\left( {1.99 - 2} \right) + \sin \left( 2 \right) = 0.9135 \cr & x = 2 \to T\left( 2 \right) = \cos \left( 2 \right)\left( {2 - 2} \right) + \sin \left( 2 \right) = 0.9093 \cr & x = 2.01 \to T\left( {2.01} \right) = \cos \left( 2 \right)\left( {2.01 - 2} \right) + \sin \left( 2 \right) = 0.9051 \cr & x = 2.1 \to T\left( {2.1} \right) = \cos \left( 2 \right)\left( {2.1 - 2} \right) + \sin \left( 2 \right) = 0.8677 \cr & \cr & {\text{Therefore}} \cr} $$ \[\boxed{\begin{array}{*{20}{c}} x&{1.9}&{1.99}&2&{2.01}&{2.1} \\ {f\left( x \right)}&{0.9463}&{0.9134}&{0.9093}&{0.9051}&{0.8632} \\ {T\left( x \right)}&{0.9509}&{0.9135}&{0.9093}&{0.9051}&{0.8677} \end{array}}\]
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