Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 3 - Review - Exercises - Page 270: 6

Answer

$y'=cos^{-1}(x)-\frac{x}{\sqrt{1-x^2}}$

Work Step by Step

Start with the function $y=xcos^{-1}(x)$. Use the product rule and inverse cosine rules to differentiate: $y'=1*cos^{-1}(x)+x*(-\frac{1}{\sqrt{1-x^2}})$. Simplify to arrive at answer: $y'=cos^{-1}(x)-\frac{x}{\sqrt{1-x^2}}$.
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