Answer
This is not true.
Work Step by Step
This is not true.
The function $$f(x)=\left\{_{1,\quad x\geq 0}^{-1,\quad x<0}\right.$$ is not continuous at $x=0$, but the function $|f(x)|=1$ is continuous.
Calculus: Early Transcendentals 9th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1337613924
ISBN 13:
978-1-33761-392-7
Chapter 2 - Review - True-False Quiz - Page 167: 25
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