Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 2 - Review - True-False Quiz - Page 167: 16

Answer

True.

Work Step by Step

$\lim\limits_{x \to 2} 4x^{2} - 11 = $ $\lim\limits_{x \to 2} 4(2)^{2} - 11 = 16 - 11 = 5$ So it's true that the function is continuous at $5$; $f(5) = 2$.
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