Answer
$19.6\;lb$.
Work Step by Step
The given values are
The given values are
Mechanical advantage $MA=125:1$.
Force applied to the small piston $F_s=2450\;lb$.
Formula for the mechanical advantage is
$\Rightarrow MA=\frac{F_l}{F_s}$
Substitute all the values.
$\Rightarrow \frac{125}{1}=\frac{2450\;lb}{F_s}$
Cross multiply.
$\Rightarrow 125F_s=2450\;lb$
Divide both sides by $125$.
$\Rightarrow 125F_s=2450\;lb$
Hence, the $F_l$ is $19.6\;lb$.
