Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.3 - Direct Variation - Exercises - Page 284: 36

Answer

$48\;lb$.

Work Step by Step

The given values are The given values are $F_l=2400\;lb$. $MA=\frac{50}{1}$ Formula for the mechanical advantage is $\Rightarrow MA=\frac{F_l}{F_s}$ Substitute all the values. $\Rightarrow \frac{50}{1}=\frac{2400\;lb}{F_s}$ Cross multiply. $\Rightarrow 50F_s=2400\;lb$ Divide both sides by $50$. $\Rightarrow F_s=48\;lb$ Hence, the $F_s$ is $48\;lb$.
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