Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.3 - Direct Variation - Exercises - Page 284: 20

Answer

$0.5\;cm$.

Work Step by Step

The number of spaces for the diameter $=1$. Let the actual measurement is $=x$. $\Rightarrow \frac{scale \;measurement \;1}{actual\;measurement\;1}=\frac{scale \;measurement \;2 }{actual\;measurement\;2}$ $\Rightarrow \frac{1\;space}{0.5\;cm}=\frac{1\;space}{x}$ Cross multiply. $\Rightarrow x=0.5\;cm$.
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