Answer
$238,500\;lb$.
Work Step by Step
The given values are
The given values are
Mechanical advantage $MA=90:1$.
Force applied to the small piston $F_s=2650\;lb$.
Formula for the mechanical advantage is
$\Rightarrow MA=\frac{F_l}{F_s}$
Substitute all the values.
$\Rightarrow \frac{90}{1}=\frac{F_l}{2650\;lb}$
Cross multiply.
$\Rightarrow 238,500\;lb=F_l$
Hence, the $F_l$ is $238,500\;lb$.