Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.3 - Direct Variation - Exercises - Page 284: 35

Answer

$9:1$

Work Step by Step

The given values are The given values are Force on small piston $F_s=400\;lb$. Force on large piston $F_l=3600\;lb$. Formula for the mechanical advantage is $\Rightarrow MA=\frac{F_l}{F_s}$ Substitute all the values. $\Rightarrow MA=\frac{3600\;lb}{400\;lb}$ Simplify. $\Rightarrow MA=\frac{9}{1}$ Hence, the $MA$ is $9:1$.
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