Answer
$$R_2=16.0\ \Omega.$$
Work Step by Step
We have
$$\frac{1}{R_2}=\frac{1}{R}-\frac{1}{R_1}=\frac{1}{5.76\ \Omega}-\frac{1}{9\ \Omega}=0.174-0.111 =0.063$$
That is $$R_2=\dfrac{1}{0.063}=15.873\approx 16.0\ \Omega.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 6 - Section 6.9 - Reciprocal Formulas Using a Calculator - Exercises - Page 261: 2
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
