Answer
$R=318~\Omega$.
Work Step by Step
Given
$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}$
$R=80\Omega, R_{1}=175\Omega, R_{2}=275\Omega,R_{3}=?$
$\frac{1}{80}=\frac{1}{175}+\frac{1}{275}+\frac{1}{R_{3}}$
$\frac{1}{R_{3}}=\frac{1}{80}-(\frac{1}{175}+\frac{1}{275})$
Therefore, $R=318\Omega$
How to use the calculator:
$80*x^{-1}-175*x^{-1}+275*x^{-1}=x^{-1}=$