Answer
$R_{1}=238~\Omega$
Work Step by Step
Given
$\frac{1}{R}=\frac{1}{R_{1}}+\frac{1}{R_{2}}+\frac{1}{R_{3}}$
$R=145~\Omega, R_{1}=?, R_{2}=875~\Omega,R_{3}=645~\Omega$
$\frac{1}{145}=\frac{1}{R_{1}}+\frac{1}{875}+\frac{1}{645}$
$\frac{1}{R_{1}}=\frac{1}{145}-(\frac{1}{875}+\frac{1}{645})$
Therefore, $R_{1}=238~\Omega$
How to use the calculator:
$145*x^{-1}-875*x^{-1}+645*x^{-1}=x^{-1}=$