Answer
$C=6.00~\mu F$.
Work Step by Step
Given
$\frac{1}{C}=\frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}}$
$C=?, C_{1}=12~\mu F, C_{2}=24~\mu F,C_{3}=24~\mu F$
$\frac{1}{C}=\frac{1}{12}+\frac{1}{24}+\frac{1}{24}$
Therefore, $C=6.00~\mu F$
How to use the calculator:
$12*x^{-1}+24*x^{-1}+24*x^{-1}=x^{-1}=$
