Answer
$$24x^2-6y^2-78x-39y .$$
Work Step by Step
We multiply each term of the first polynomial by each term of the second polynomial. Then we add the products, as follows $$ (4x - 2y - 13)(6x + 3y)= 4x (6x + 3y) - 2y (6x + 3y)- 13(6x + 3y)\\ =24x^2+12xy-12xy-6y^2-78x-39y\\ = 24x^2-6y^2-78x-39y .$$