Answer
$10y^3 -24y^2 -32y+16$
Work Step by Step
We multiply each term of the first polynomial by each term of the second polynomial. Then we add the products, as follows
$$
(2y^2 - 4y - 8)(5y - 2)= 2y^2 (5y - 2) - 4y (5y - 2) - 8(5y - 2)\\
= 10y^3 -4y^2-20y^2+8y-40y+16\\
=10y^3 -24y^2 -32y+16
.$$
