Answer
$m^3-8$
Work Step by Step
We multiply each term of the first polynomial by each term of the second polynomial. Then we add the products, as follows
$$
(m^2 + 2m+ 4)(m - 2)=m^2 (m - 2)+ 2m(m - 2)+4(m - 2)\\
= m^3-2m^2+2m^2-4m+4m-8\\
= m^3-8
.$$
