Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.10 - Spheres - Exercise - Page 438: 6

Answer

$103\ m^2.$

Work Step by Step

The material needed for the balloon is the surface area of the sphere $A=4\pi r^2=4 \pi (5.72/2)^2=102.78\ m^2\approx 103\ m^2.$
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