Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.10 - Spheres - Exercise - Page 438: 4

Answer

a. $1330\ ft^2.$ b. $4580\ ft^3.$

Work Step by Step

a. The area of the sphere is $A=4\pi r^2=4 \pi (20.6/2)^2=1333.166\ ft^2\approx 1330\ ft^2.$ b. The volume of the sphere is $V=\frac{4}{3}\pi r^3=\frac{4}{3} \pi (20.6/2)^3= 4577.20\ ft^3 \approx 4580\ ft^3.$
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