Answer
$114,000\ m^3.$
Work Step by Step
The helium needed to fill the sphere is given by the volume of the sphere:
$V=\frac{4}{3}\pi r^3=\frac{4}{3} \pi (30.1)^3= 114232.08\ m^3 \approx 114,000\ m^3.$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 12 - Section 12.10 - Spheres - Exercise - Page 438: 5
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