Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.10 - Spheres - Exercise - Page 438: 3

Answer

a. $4,120\ in^2.$ b. $24,800\ in^3.$

Work Step by Step

a. The area of the sphere is $A=4\pi r^2=4 \pi (36.2/2)^2=4116.86\ in^2\approx 4,120\ in^2.$ b. The volume of the sphere is $V=\frac{4}{3}\pi r^3=\frac{4}{3} \pi (36.2/2)^3= 24838.44\ in^3 \approx 24,800\ in^3.$
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