Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.10 - Spheres - Exercise - Page 438: 2

Answer

a. $4390\ cm^2.$ b. $27,400\ cm^3.$

Work Step by Step

a. The area of the sphere is $A=4\pi r^2=4 \pi (18.7)^2=4394.33\ cm^2\approx 4390\ cm^2.$ b. The volume of the sphere is $V=\frac{4}{3}\pi r^3=\frac{4}{3} \pi (18.7)^3= 27391.34\ cm^3 \approx 27400\ cm^3.$
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