Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Section 11.2 - The Quadratic Formula - Exercise - Page 367: 34

Answer

$2.752, \ or, \ -0.413$

Work Step by Step

For the equation $18.9x^2 -44.2x-21.5= 0$, we use the quadratic formula as follows $$ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}, \\ a=18.9, \quad b=-44.2, \quad c=-21.5 .$$ That is, $$ x=\frac{44.2\pm \sqrt{44.2^2-4(18.9)(-21.5)}}{2(18.9) }=2.752, \ or, \ -0.413 .$$
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