Answer
$1.25, \ or, \ -\frac{7}{12}=-0.583$
Work Step by Step
For the equation $48x^2 -32x-35 = 0$, we use the quadratic formula as follows
$$
x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a},
\\
a=48, \quad b=-32, \quad c=-35
.$$
That is, $$ x=\frac{32 \pm \sqrt{32^2-4(48)(-35)}}{2(48) }=1.25, \ or, \ -\frac{7}{12}=-0.583
.$$
Check the result:
$$
48(1.25)^2 -32(1.25)-35 =35-35=0, \quad
48(-0.583)^2 -32(-0.583)-35 \approx 35-35=0
.
$$
