Answer
$\frac{5}{4}\approx1.25, \ or, \ -\frac{5}{4}\approx-1.25$
Work Step by Step
For the equation $16x^2 -25= 0$, we use the quadratic formula as follows
$$
x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a},
\\
a=16, \quad b=0, \quad c=-25
.$$
That is, $$ x=\frac{0\pm \sqrt{0-4(16)(-25)}}{2(16) }=\frac{5}{4}\approx1.25, \ or, \ -\frac{5}{4}\approx-1.25
.$$
