Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Section 11.2 - The Quadratic Formula - Exercise - Page 367: 26

Answer

$\frac{2}{3}\approx0.667, \ or, \ \frac{5}{3}\approx1.667$

Work Step by Step

For the equation $9x^2 -21x+10= 0$, we use the quadratic formula as follows $$ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}, \\ a=9, \quad b=-21, \quad c=10 .$$ That is, $$ x=\frac{21\pm \sqrt{21^2-360}}{2(9) }=\frac{2}{3}\approx0.667, \ or, \ \frac{5}{3}\approx1.667$$
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