Answer
$13x\sqrt[3]{6x}$
Work Step by Step
$x\sqrt[3]{48x}+11\sqrt[3]{6x^4}$
Factor out perfect cubes.
$x\sqrt[3]{(8)(6)(x)}+11\sqrt[3]{6x^3x}$
Simplify.
$x(2)\sqrt[3]{6x}+11(x)\sqrt[3]{6x}$
$2x\sqrt[3]{6x}+11x\sqrt[3]{6x}$
Add like radicals.
$13x\sqrt[3]{6x}$
