Answer
$5+2\sqrt6$
Work Step by Step
$(\sqrt2+\sqrt3)^2$=
$(\sqrt{2}+\sqrt3)(\sqrt{2}+\sqrt3)$
Use the FOIL method to multiply the binomial.
Multiply the First terms, the Outside terms, the Inside terms, and the Last terms.
$(\sqrt{2}\times\sqrt{2})+(\sqrt2\times(\sqrt3))+(\sqrt2\times\sqrt3)+(\sqrt3\times(\sqrt3))$
Simplify.
$2+\sqrt{6}+\sqrt6+3$
Combine like terms/like radicals.
$5+2\sqrt6$
