Answer
$-14$
Work Step by Step
RECALL:
(i) $(a+b)(a-b) = a^2-b^2$
(ii) $\sqrt{a}^2=a, a \ge0$
Use rule (i) above to obtain:
$=\sqrt{11}^2-5^2
\\=\sqrt{11}^2-25$
Use rule (ii) above to obtain:
$=11-25
\\=-14$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set - Page 592: 67
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