Answer
$-\sqrt[3]3$
Work Step by Step
$7\sqrt[3]{24}-5\sqrt[3]{81}$
Factor out perfect cubes.
$7\sqrt[3]{(8)(3)}-5\sqrt[3]{(27)(3)}$
Simplify.
$7(2)\sqrt[3]{3}-5(3)\sqrt[3]{3}$
$14\sqrt[3]3-15\sqrt[3]3$
Add like radicals.
$-\sqrt[3]3$
Introductory Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-805-X
ISBN 13:
978-0-13417-805-9
Chapter 8 - Section 8.3 - Operations with Radicals - Exercise Set - Page 592: 84
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