Answer
a) $-8x$
b) $-8\sqrt[3] 2$
Work Step by Step
a) we have $4x-12x$
Thus, Take the common terms out, we have $4x-12x=4x(1-3)=4x(-2)=-8x$
when we combine same terms we will have the result : $-8x$
b) we have $x=\sqrt[3] 2$
Thus, $4x-12x=4 \sqrt[3] 2 -12 \sqrt[3] 2= \sqrt[3] 2(4-12)=-8\sqrt[3] 2$
when we combine same radicals we will have the result : $-8\sqrt[3] 2$