Answer
$(4x-3)(16x^2+12x+9)$.
Work Step by Step
The given expression is
$64x^3-27$.
We can write $(4x)^3-3^3$.
The formula for factoring is
$A^3-B^3=(A-B)(A^2+AB+B^2)$
Substitute $A=4x$ and $B=3$ into the formula.
$(4x)^3-3^3=(4x-3)((4x)^2+4x\cdot 3+3^2)$
$(4x)^3-3^3=(4x-3)(16x^2+12x+9)$
Hence, the factor is $(4x-3)(16x^2+12x+9)$.
