Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.3 - Multiplying and Simplifying Radical Expressions - Exercise Set - Page 533: 111

Answer

False

Work Step by Step

Since, $ 2\sqrt 5 \cdot 5 \sqrt 5=(2 \cdot 5) (\sqrt 5 \cdot \sqrt 5)=10 \cdot 5=50$ Hence, the statement false.
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