Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 521: 11

Answer

$729$

Work Step by Step

$(a^m)^n=a^{mn}$ Thus $81^{\frac{3}{2}}=(9^2)^{\frac{3}{2}}=9^{2\cdot\frac{3}{2}}=9^3=729$
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