Answer
$28$
Work Step by Step
$(a^m)^n=a^{mn}$
Thus $4^{\frac{5}{2}}-8^{\frac{2}{3}}=(2^2)^{\frac{5}{2}}-(2^3)^{\frac{2}{3}}=2^{2\cdot\frac{5}{2}}-2^{3\cdot\frac{2}{3}}=2^5-2^2=32-4=28$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 7 - Section 7.2 - Rational Exponents - Exercise Set - Page 521: 18
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