Answer
$-4$
Work Step by Step
RECALL:
$a^{\frac{1}{n}}=\sqrt[n]{a}$
$\sqrt [n] {a^{n}}=a$
With $n=3$, use the rules above to obtain:
$(-64)^{\frac{1}{3}}=\sqrt[3]{-64}=\sqrt [3] {-4^{3}}=-4$
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