Answer
{$\dfrac{1}{9},1$}
Work Step by Step
Given: $|3x+1|=|6x-2|$
or,$3x+1=6x-2$ and $3x+1=-(6x-2)$
or, $3x-6x=-2-1$ and $3x+1=-6x+2$
or, $-3x=-3$ and $3x+6x=2-1$
or, $x=1$ and $x=\dfrac{1}{9}$
Hence, {$\dfrac{1}{9},1$}
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 284: 78
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