Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 284: 59

Answer

$(-\infty,-5]\cup[3,\infty)$. The graph is shown below.

Work Step by Step

The given expression is $\Rightarrow \left | \frac{2x+2}{4}\right |\geq2$ Rewrite the inequality without absolute value bars. $\Rightarrow \frac{2x+2}{4}\leq-2$ or $\frac{2x+2}{4}\geq2$ Solve each inequality separately. Multiply all parts by $4$. $\Rightarrow \frac{2x+2}{4}(4)\leq-2(4)$ or $\frac{2x+2}{4}(4)\geq2(4)$ Simplify. $\Rightarrow 2x+2\leq-8$ or $2x+2\geq8$ Add $-2$ to all parts. $\Rightarrow 2x+2-2\leq-8-2$ or $2x+2-2\geq8-2$ Simplify $\Rightarrow 2x\leq-10$ or $2x\geq6$ Divide all parts by $2$. $\Rightarrow \frac{2x}{2}\leq\frac{-10}{2}$ or $\frac{2x}{2}\geq\frac{6}{2}$ Simplify. $\Rightarrow x\leq-5$ or $x\geq3$ The solution set is less than or equal to $-5$ or greater than or equal to $3$. The interval notation is $(-\infty,-5]\cup[3,\infty)$.
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