Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 4 - Section 4.3 - Equations and Inequalities Involving Absolute Value - Exercise Set - Page 284: 74

Answer

$(-\infty,-4]\cup[\frac{1}{2},\infty)$. The graph is shown below.

Work Step by Step

The given expression is $\Rightarrow 9\leq \left | 4x+7\right |$ Switch sides. $\Rightarrow \left | 4x+7\right | \geq 9$ Rewrite the inequality without absolute value bars. $\Rightarrow 4x+7\leq-9$ or $4x+7\geq9$ Solve each inequality separately. Subtract $7$ from all parts. $\Rightarrow 4x+7-7\leq-9-7$ or $4x+7-7\geq9-7$ Simplify. $\Rightarrow 4x\leq-16$ or $4x\geq2$ Divide all parts by $4$. $\Rightarrow \frac{4x}{4}\leq\frac{-16}{4}$ or $\frac{4x}{4}\geq\frac{2}{4}$ Simplify. $\Rightarrow x\leq-4$ or $x\geq\frac{1}{2}$ The solution set is les than or equal to $-1$ or greater than or equal to $2$. The interval notation is $(-\infty,-4]\cup[\frac{1}{2},\infty)$.
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