Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises - Page 100: 96

Answer

$-\dfrac{12}{x^7}$

Work Step by Step

RECALL: (i) $a^m \cdot a^n = a^{m+n}$ (ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$ Multiply the numerical coefficients then use rule (i) above to obtain: $=-12x^{4+(-11)} \\=-12x^{-7}$ Use rule (ii) above to obtain: $=-12 \cdot \dfrac{1}{x^7} \\=-\dfrac{12}{x^7}$
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