Answer
$-\dfrac{8}{y^7}$
Work Step by Step
RECALL:
(i) $\dfrac{a^m}{a^n} = a^{m-n}, a\ne0$
(ii) $a^{-m} = \dfrac{1}{a^m}, a\ne0$
Divide the numerical coefficients then use rule (i) above to obtain:
$=-8y^{3-10}
\\=-8y^{-7}$
Use rule (ii) above to obtain:
$=-8 \cdot \dfrac{1}{y^7}
\\=-\dfrac{8}{y^7}$
