Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises - Page 100: 91

Answer

$\dfrac{x^2}{y^5}$

Work Step by Step

RECALL: $a^{-m}=\dfrac{1}{a^{m}}, a\ne0$ Use the rule above to obtain: $=x^2 \cdot \dfrac{1}{y^5} \\=\dfrac{x^2}{y^5}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.