Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Review Exercises - Page 100: 93

Answer

$\dfrac{1}{x^{18}}$

Work Step by Step

RECALL: (i) $a^{-m}=\dfrac{1}{a^{m}}, a\ne0$ (ii) $(a^m)^n=a^{mn}$ Use rule (ii) above to obtain: $=x^{3(-6)} \\=x^{-18}$ Use rule (i) above to obtain: $=\dfrac{1}{x^{18}}$
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