Answer
$\dfrac{1}{x^{18}}$
Work Step by Step
RECALL:
(i) $a^{-m}=\dfrac{1}{a^{m}}, a\ne0$
(ii) $(a^m)^n=a^{mn}$
Use rule (ii) above to obtain:
$=x^{3(-6)}
\\=x^{-18}$
Use rule (i) above to obtain:
$=\dfrac{1}{x^{18}}$
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