Answer
$x=7$
Work Step by Step
If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x$ and every real number $y$.
Therefore, $log_{x}49=2$ is equivalent to $x^{2}=49$.
We can now solve for x. Take the square root of both sides.
$(x^{2})^{\frac{1}{2}}=(49)^{\frac{1}{2}}$
$x=7$
