Answer
$3^{-4}=\frac{1}{81}$
Work Step by Step
If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x$ and every real number $y$.
Therefore, $\log_{3}\frac{1}{81}=-4$ means $3^{-4}=\frac{1}{3^{4}}=\frac{1}{81}$.
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