Answer
$log_{4}\frac{1}{16}=-2$
Work Step by Step
We are given $10^{-2}=\frac{1}{100}$.
If $b\gt0$ and $b\ne1$, then $y=log_{b}x$ means $x=b^{y}$ for every $x$ and every real number $y$.
Therefore, $4^{-2}=\frac{1}{4^{2}}=\frac{1}{16}$ is equivalent to $log_{4}\frac{1}{16}=-2$.
