Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 597: 85

Answer

-1

Work Step by Step

A natural logarithm is a logarithm to base $e$. As shown on page 582, when a natural logarithm is written in the form $ln (x)$, this is equivalent to the expression $log_{e}x$. Therefore, $ln \frac{1}{e}=log_{e}\frac{1}{e}=-1$. We know this, because $(e)^{-1}=\frac{1}{e^{1}}=\frac{1}{e}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.