Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Review - Page 597: 81

Answer

$ln(1.25)\approx.2231$

Work Step by Step

To approximate $ln(1.25)$ on a calculator, we can press the following sequence of keys. 1. 1.25 then LN (OR) 2. LN then 1.25 then ENTER To four decimal places, $ln(1.25)\approx.2231$
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