Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 600: 22

Answer

$k=\frac{1}{24}$, $y=\frac{1}{24}x$

Work Step by Step

We know that the direct variation equation is in the form $y=kx$ (where k is the constant of variation). Therefore, we can plug in the given values to find the value of k. $\frac{1}{2}=12k$ Divide both sides by 12. $k=\frac{1}{24}$ So the direct variation equation is $y=\frac{1}{24}x$.
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