Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 600: 11c

Answer

$x-7$

Work Step by Step

Adding the numerators, copying the denominator, and then cancelling the common factor between the numerator and the denominator result to \begin{array}{l} \dfrac{x^2}{x+7}-\dfrac{49}{x+7} \\\\= \dfrac{x^2-49}{x+7} \\\\= \dfrac{(x+7)(x-7)}{x+7} \\\\= x-7 .\end{array}
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