Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Cumulative Review - Page 600: 19e

Answer

4x

Work Step by Step

$\sqrt[3] (64x^{3})=\sqrt[3] (64\times x^{3})=\sqrt[3] 64\times\sqrt[3](x^{3})=4x$ We know this because $4^{3}=64$ and $(x)^{3}=x^{3}$.
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